-5x^2+960x+14400=0

Solution for -5x^2+960x+14400=0 equation:

-5x^2+960x+14400=0

a = -5; b = 960; c = +14400;
Δ = b2-4ac
Δ = 9602-4·(-5)·14400
Δ = 1209600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1209600}=\sqrt{57600*21}=\sqrt{57600}*\sqrt{21}=240\sqrt{21}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(960)-240\sqrt{21}}{2*-5}=\frac{-960-240\sqrt{21}}{-10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(960)+240\sqrt{21}}{2*-5}=\frac{-960+240\sqrt{21}}{-10}
$